In the given network capacitance C 2 = 10 µF, C 1 = 5 µF and C 3 = 4 µF. The resultant capacitance between P and Q will be:
Text Solution
Verified by ExpertsThe correct answer is:
C
Seeing in the given circuit C 1 and C 2 are connected in parallel. Hence, their equivalent capacitance
C eq = C 1 + C 2 = 5 + 10
= 15 µF
As C eq and C 3 are connected in series, Hence, resultant capacitance between P and Q is given by
C PQ = 
= 3.2 µF
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